#### Answer

$\frac{1}{4}$

#### Work Step by Step

P(E) = $\frac{no.\ of\ outcomes\ in\ favor}{Total\ no.\ of\ outcomes}$
A single die is rolled twice. The 36 equally likely outcomes are shown in the attached picture.
E: two even numbers
Favorable outcomes= { (2,2),(2,4),(2,6),(4,2),(4,4),(4,6),(6,2),(6,4),(6,6)}
P(E) = $\frac{9}{36}$ = $\frac{1}{4}$