## Thinking Mathematically (6th Edition)

$\frac{3}{10}$ = 0.3
P(E) = $\frac{no.\ of\ outcomes\ in\ favor}{Total\ no.\ of\ outcomes}$ It is equally probable that the pointer will land on any one of the ten colored regions, and we spin again if we land on a borderline. There are 10 total regions. E : A brown region There are three regions of brown. Favorable outcomes= {3 Regions} P(E) = $\frac{3}{10}$