Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 8 - Section 8.2 - Perimeter and Area of Polygons - Exercises - Page 370: 9

Answer

84 $in^{2}$

Work Step by Step

Given sides of a triangle 13 in, 14 in, 15 in Using Heron's formula if three sides of a triangle have length a,b,c then area A of a triangle is A = $\sqrt s(s-a)(s-b)(s-c)$ where s = $\frac{a+b+c}{2}$ Lets take a=13 b=14 and c=15 s = $\frac{13+14+15}{2}$ = 21 in A = $\sqrt 21(21-13)(21-14)(21-15)$ =$\sqrt 21*8*7*6$ =84 $in^{2}$
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