Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 8 - Section 8.2 - Perimeter and Area of Polygons - Exercises - Page 370: 14

Answer

240 $m^{2}$

Work Step by Step

The area of a trapezoid whose bases have lengths b1 and b2 and altitude has length of h is given by A = $\frac{1}{2}$*h(b1+b2) Lets take b1 = BC = 20m b2 =AD = 12m h = 15 m Therefore A = $\frac{1}{2}$*15* (12+20) = 15*(16) = 240 $m^{2}$
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