Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 8 - Section 8.2 - Perimeter and Area of Polygons - Exercises - Page 370: 23b

Answer

$\frac{4}{1}$

Work Step by Step

The length of the sides of the first triangle are 6 in, 8 in, 10 in second triangle are 3 in, 4 in, 5 in $\frac{6}{3}$ = $\frac{10}{5}$ =$\frac{8}{4}$ = $\frac{2}{1}$ $\frac{A1}{A2}$ = $(\frac{s1}{s2})^{2}$ = $(\frac{2}{1})^{2}$ = $\frac{4}{1}$
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