Elementary Geometry for College Students (7th Edition)

$\frac{4}{1}$
The length of the sides of the first triangle are 6 in, 8 in, 10 in second triangle are 3 in, 4 in, 5 in $\frac{6}{3}$ = $\frac{10}{5}$ =$\frac{8}{4}$ = $\frac{2}{1}$ $\frac{A1}{A2}$ = $(\frac{s1}{s2})^{2}$ = $(\frac{2}{1})^{2}$ = $\frac{4}{1}$