## Elementary Geometry for College Students (7th Edition) Clone

192 $units^{2}$
By using pythagoras theorem in right triangle ABD $BD^{2}$ =$AB^{2}$ + $AD^{2}$ $20^{2}$ = $12^{2}$ + $AD^{2}$ $AD^{2}$ = $20^{2}$- $12^{2}$ = 400 - 144= 256 AD = $\sqrt 256$ = 16 We know in kites adjacent sides are equal AB =BC =12 AD = CD = 16 The area of Kite ABCD = Area of $\triangle$ ABD + Area of $\triangle$ BCD = $\frac{1}{2}$*AD*AB + $\frac{1}{2}$*DC*BC = $\frac{1}{2}$*16*12 + $\frac{1}{2}$*16*12 = 96 + 96 = 192 $units^{2}$