#### Answer

20 $unit^{2}$

#### Work Step by Step

The area of any quadrilateral with perpendicular diagonals of length d1 and d2 is given by
A =$\frac{1}{2}$ d1 * d2
d1 = AC= 8
d2 = BD = 5
The area of ABCD = \frac{1}{2}$ *8* 5 = 20 $unit^{2}$

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Published by
Cengage

ISBN 10:
978-1-337-61408-5

ISBN 13:
978-1-33761-408-5

20 $unit^{2}$

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