Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 8 - Section 8.2 - Perimeter and Area of Polygons - Exercises - Page 370: 27

Answer

A$\approx$42.33

Work Step by Step

An inscribed angle that intercepts a semicircle is always a right angle. Therefore angles D and B are right angles. AD$^2$=AC$^2$-CD$^2$ AD$^2$=100-16 AD=$\sqrt {84}$ BA$^2$=AC$^2$-BC$^2$ BA$^2$=100-36=64 BA=8 A=.5(4)($\sqrt {84}$)+.5(6)(8) A=2$\sqrt {84}$+24 A$\approx$42.33
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