Elementary Geometry for College Students (7th Edition) Clone

Published by Cengage
ISBN 10: 978-1-337-61408-5
ISBN 13: 978-1-33761-408-5

Chapter 8 - Section 8.2 - Perimeter and Area of Polygons - Exercises - Page 370: 19

Answer

32in, 16 in , 28 in

Work Step by Step

Lets take length of second side be x in Length of third side be 12 more than the second side= x+12 in Length of first side be twice of second side = 2x Perimeter of triangle = length of first side + second side+ third side 76 = 2x + x+ x+12 76 = 4x + 12 4x = 76 - 12 = 64 x = $\frac{64}{4}$ = 16 in Therefore Length of first side = 2x = 2*16 = 32in Length of second side = 16in length of third side = x+12 = 16 + 12 = 28in
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