$16x^2-9y^2 = (4x+3y)~(4x-3y)$
Work Step by Step
The general form of factoring the difference of two squares is as follows: $x^2-y^2 = (x+y)~(x-y)$ We can factor the difference of the two squares: $16x^2-9y^2 = (4x+3y)~(4x-3y)$
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