Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Appendix A - A.4 - Quadratic Equations - Exercises - Page 550: 1

Answer

$ax^2+5ax+7a = (a)~(x^2+5x+7)$

Work Step by Step

The GCF of $~[ax^2+5ax+7a]~$ is $~a$ We can factor by using the GCF: $ax^2+5ax+7a = (a)~(x^2+5x+7)$
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