## Elementary Geometry for College Students (6th Edition)

$x = -\frac{3}{4}~~$ or $~~x = \frac{3}{4}$
The general form of factoring the difference of two squares is as follows: $x^2-y^2 = (x+y)~(x-y)$ Let's consider the given equation: $16x^2-9 = 0$ $(4x+3)~(4x-3) = 0$ $4x+3 = 0~~$ or $~~4x-3 = 0$ $x = -\frac{3}{4}~~$ or $~~x = \frac{3}{4}$