Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Appendix A - A.4 - Quadratic Equations - Exercises - Page 550: 34

Answer

$x = -\frac{3}{4}~~$ or $~~x = \frac{3}{4}$

Work Step by Step

The general form of factoring the difference of two squares is as follows: $x^2-y^2 = (x+y)~(x-y)$ Let's consider the given equation: $16x^2-9 = 0$ $(4x+3)~(4x-3) = 0$ $4x+3 = 0~~$ or $~~4x-3 = 0$ $x = -\frac{3}{4}~~$ or $~~x = \frac{3}{4}$
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