Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Appendix A - A.4 - Quadratic Equations - Exercises - Page 550: 3

Answer

$2bx^2+4b^2x = (2bx)~(x+2b)$

Work Step by Step

The GCF of $~[2bx^2+4b^2x]~$ is $~2bx$ We can factor by using the GCF: $2bx^2+4b^2x = (2bx)~(x+2b)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.