#### Answer

$x=2~$ or $~x=4$

#### Work Step by Step

Let's consider a trinomial in this form: $~x^2+bx+c$
To factor this trinomial, we need to find two numbers $r$ and $s$ such that $r+s = b$ and $r\times s = c$
Then we can factor the trinomial as follows:
$~x^2+bx+c = (x+r)~(x+s)$
Let's consider this equation: $~x^2-6x+8=0$
To factor the left side of the equation, we need to find two numbers $r$ and $s$ such that $r+s = -6$ and $r\times s = 8$. We can see that $(-4)+(-2) = -6~$ and $(-4)\times (-2) = 8$
We can solve the equation as follows:
$x^2-6x+8=0$
$(x-4)(x-2)=0$
$x=4~$ or $~x=2$