Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Appendix A - A.4 - Quadratic Equations - Exercises - Page 550: 5

Answer

$y^2-9 = (y+3)~(y-3)$

Work Step by Step

The general form of factoring the difference of two squares is as follows: $x^2-y^2 = (x+y)~(x-y)$ We can factor the difference of the two squares: $y^2-9 = (y+3)~(y-3)$
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