Elementary Geometry for College Students (6th Edition)

Published by Brooks Cole
ISBN 10:
ISBN 13:

Appendix A - A.4 - Quadratic Equations - Exercises - Page 550: 35

Answer

$y = -\frac{5}{2}~~$ or $~~y = \frac{5}{2}$

Work Step by Step

The general form of factoring the difference of two squares is as follows: $x^2-y^2 = (x+y)~(x-y)$ We can rearrange and solve the given equation as follows: $4y^2 = 25$ $4y^2 - 25 = 0$ $(2y+5)~(2y-5) = 0$ $2y+5 = 0~~$ or $~~2y-5 = 0$ $y = -\frac{5}{2}~~$ or $~~y = \frac{5}{2}$
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