Answer
a) $x^{\frac{2}{3}}+C$
b) $x^{\frac{1}{3}}+C$
c) $x^{\frac{-1}{3}}+C$
Work Step by Step
a) The anti-derivative is:
$\dfrac{2}{3}\dfrac{x^{-1/3+1}}{-1/3+1}+C=x^{\frac{2}{3}}+C$
b) The anti-derivative is:
$\dfrac{1}{3}\dfrac{x^{-2/3+1}}{-2/3+1}+C=x^{\frac{1}{3}}+C$
c) The anti-derivative is:
$\dfrac{-1}{3}\dfrac{x^{-4/3+1}}{-4/3+1}+C= x^{\frac{-1}{3}}+C$