Answer
a) $\dfrac{1}{3} e^{3x}+C$
b) $- e^{-x}+C$
c) $2 e^{x/2}+C $
Work Step by Step
a) The anti-derivative is: $\int (e^{3x}) dx=\dfrac{1}{3} e^{3x}+C$
b) The anti-derivative is:
$\int e^{-x} dx=- e^{-x}+C$
c) The anti-derivative is:
$ \dfrac{1}{1/2} e^{x/2}+C=2 e^{x/2}+C $
