## University Calculus: Early Transcendentals (3rd Edition)

a) $\dfrac{1}{3} e^{3x}+C$ b) $- e^{-x}+C$ c) $2 e^{x/2}+C$
a) The anti-derivative is: $\int (e^{3x}) dx=\dfrac{1}{3} e^{3x}+C$ b) The anti-derivative is: $\int e^{-x} dx=- e^{-x}+C$ c) The anti-derivative is: $\dfrac{1}{1/2} e^{x/2}+C=2 e^{x/2}+C$