## University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson

# Chapter 4 - Section 4.8 - Antiderivatives - Exercises - Page 271: 2

#### Answer

a) $3x^2+C$ b) $\dfrac{1}{8}x^8+C$ c) $\dfrac{1}{8}x^8-3x^2+8x+C$

#### Work Step by Step

a) The anti-derivative is: $\dfrac{6}{1+1}x^{1+1}+C=3x^2+C$ b) The anti-derivative is: $\dfrac{1}{7+1}x^{7+1}+C=\dfrac{1}{8}x^8+C$ c) The anti-derivative is: $\dfrac{1}{7+1}x^{7+1}-\dfrac{6}{1+1}x^{1+1}+(8)x^{0+1}+C=\dfrac{1}{8}x^8-3x^2+8x+C$

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