Answer
a) $\dfrac{1}{x^{2}}+C$
b) $\dfrac{-1}{4x^{2}}+C$
c) $\dfrac{x^4}{4}+\dfrac{1}{2x^{2}}+C$
Work Step by Step
a) The anti-derivative is:
$(-2)\dfrac{x^{-3+1}}{-3+1}+C=\dfrac{1}{x^{2}}+C$
b) The anti-derivative is:
$\dfrac{1}{2}\dfrac{x^{-3+1}}{-3+1}+C=\dfrac{-1}{4x^{2}}+C$
c) The anti-derivative is:
$\dfrac{x^4}{4}-\dfrac{x^{-3+1}}{-3+1}+C=\dfrac{x^4}{4}+\dfrac{1}{2x^{2}}+C$