Answer
a) $-\dfrac{1}{2} e^{-2x}+C$
b) $\dfrac{3}{4} e^{4x/3}+C$
c) $ \dfrac{1}{-1/5} e^{-x/5}+C=-5e^{-x/5}+C$
Work Step by Step
a) The anti-derivative is: $ \dfrac{1}{-2} e^{-2x}+C=-\dfrac{1}{2} e^{-2x}+C$
b) The anti-derivative is:$ \dfrac{1}{4/3} e^{4x/3}+C=\dfrac{3}{4} e^{4x/3}+C$
c) The anti-derivative is:$ \dfrac{1}{-1/5} e^{-x/5}+C=-5e^{-x/5}+C$
