University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 4 - Section 4.8 - Antiderivatives - Exercises - Page 271: 5

Answer

a) $-\dfrac{1}{x}+C$ b) $-\dfrac{5}{x}+C$ c) $2x+\dfrac{5}{x}+C$

Work Step by Step

a) The anti-derivative is: $\dfrac{x^{-2+1}}{-2+1}+C=-\dfrac{1}{x}+C$ b) The anti-derivative is: $5(-\dfrac{1}{x}+C)=-\dfrac{5}{x}+C$ c) The anti-derivative is: $2x-(\dfrac{-5}{x}+C)=2x+\dfrac{5}{x}+C$
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