University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 4 - Section 4.8 - Antiderivatives - Exercises - Page 271: 7

Answer

a) $x^{\frac{3}{2}}+C$ b) $\sqrt x+C$ c) $\dfrac{2}{3}x^{\frac{3}{2}}+2 \sqrt x+C$

Work Step by Step

a) The anti-derivative is: $\dfrac{3}{2}\dfrac{x^{1/2+1}}{1/2+1}+C=x^{\frac{3}{2}}+C$ b) The anti-derivative is: $\dfrac{1}{2}\dfrac{x^{-1/2+1}}{-1/2+1}+C=\sqrt x+C$ c) The anti-derivative is: $\dfrac{x^{1/2+1}}{1/2+1}+\dfrac{x^{-1/2+1}}{-1/2+1}+C=\dfrac{2}{3}x^{\frac{3}{2}}+2 \sqrt x+C$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.