Answer
$\lim\limits_{x \to -2}\frac{(-2x-4)}{(x^{3}+2x^{2})} = -0.5=\frac{-1}{2}$
Work Step by Step
Simplify:
$\frac{(-2x-4)}{(x^{3}+2x^{2})}= -\frac{2(x+2)}{x^{2}(x+2)} = -\frac{2}{x^{2}}$
$\lim\limits_{x \to -2}\frac{(-2x-4)}{(x^{3}+2x^{2})}= \lim\limits_{x \to -2}-\frac{2}{x^{2}} = -\frac{2}{4} = -\frac{1}{2} = -0.5$
