University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 2 - Section 2.2 - Limit of a Function and Limit Laws - Exercises: 15

Answer

$\lim\limits_{x \to 2} \frac{(2x + 5)}{(11 - x^{3})} = 3$

Work Step by Step

$\lim\limits_{x \to 2} \frac{(2x + 5)}{(11 - x^{3})} = \frac{\lim\limits_{x \to 2}(2x + 5)}{\lim\limits_{x \to 2}(11-x^{3})}$ = $\frac{2(2) + 5}{11 - 2^{3}}$ = $\frac{9}{3}$ = 3
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