## University Calculus: Early Transcendentals (3rd Edition)

$\lim\limits_{z \to 4}\sqrt {z^{2}-10} =\sqrt 6$ = 2.449
First we will calculate the limit of: $f(x) = (z^{2}-10)$ $\lim\limits_{z \to 4}(z^{2}-10) = \lim\limits_{z \to 4}z^{2} -\lim\limits_{z \to 4}10$ $= 16 -10$ $= 6$ Now, applying the limits property: $\lim\limits_{z \to 4}\sqrt (z^{2}-10) =\sqrt 6$ = 2.449