University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 2 - Section 2.2 - Limit of a Function and Limit Laws - Exercises: 20

Answer

$\lim\limits_{z \to 4}\sqrt {z^{2}-10} =\sqrt 6 $ = 2.449

Work Step by Step

First we will calculate the limit of: $f(x) = (z^{2}-10)$ $\lim\limits_{z \to 4}(z^{2}-10) = \lim\limits_{z \to 4}z^{2} -\lim\limits_{z \to 4}10$ $ = 16 -10$ $ = 6$ Now, applying the limits property: $\lim\limits_{z \to 4}\sqrt (z^{2}-10) =\sqrt 6 $ = 2.449
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