Answer
$\lim\limits_{y \to -3}(5-y)^{\frac{4}{3}} = 16$
Work Step by Step
$\lim\limits_{y \to -3}(5-y) = \lim\limits_{y \to -3}5 - \lim\limits_{y \to -3}y$ = 5+3 = 8
Thus:
$\lim\limits_{y \to -3}(5-y)^{\frac{4}{3}} = (8)^{\frac{4}{3}} = 16$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 2 - Section 2.2 - Limit of a Function and Limit Laws - Exercises - Page 66: 19
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