Answer
$\lim\limits_{s \to \frac{2}{3}} (8-3s )(2s-1) = 2$
Work Step by Step
$\lim\limits_{s \to \frac{2}{3}} (8-3s )(2s-1) = \lim\limits_{s \to 0.6\bar6} (-6s^{2} +19s -8)$
= -$\lim\limits_{s \to 0.6\bar6}6s^{2} + 19\lim\limits_{s \to 0.6\bar6}s -\lim\limits_{s \to 0.6\bar6} 8$ = $-6(0.6\bar6)^{2} + 19*0.6\bar6 - 8$ = 2
