University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 2 - Section 2.2 - Limit of a Function and Limit Laws - Exercises: 26


$\lim\limits_{x \to 2}\frac{(x^{2} - 7x +10)}{(x-2)} = \lim\limits_{x \to 2}(x-5) = -3$

Work Step by Step

Simplify: $\frac{(x^{2} - 7x +10)}{(x-2)} = \frac{(x-5)(x-2)}{(x-2)} = (x-5)$ Now, $\lim\limits_{x \to 2}\frac{(x^{2} - 7x +10)}{(x-2)} = \lim\limits_{x \to 2}(x-5) = -3$
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