University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 2 - Section 2.2 - Limit of a Function and Limit Laws - Exercises - Page 66: 25


$\lim\limits_{x \to -5}\frac{(x^{2}+3x-10)}{(x+5)} = \lim\limits_{x \to -5}(x-2) = -7$

Work Step by Step

Simplify: $\frac{(x^{2}+3x-10)}{(x+5)} = \frac{(x-2)(x+5)}{(x+5)} = (x-2)$ Now, $\lim\limits_{x \to -5}\frac{(x^{2}+3x-10)}{(x+5)} = \lim\limits_{x \to -5}(x-2) = -7$
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