Answer
$\ln 7$
Work Step by Step
Solve $\lim\limits_{(x,y,z) \to (2,-3,6)} \ln \sqrt {x^2+y^2+z^2}$
Now, $\lim\limits_{(x,y,z) \to (2,-3,6)} \ln \sqrt {x^2+y^2+z^2}=\ln \sqrt {(2)^2+(-3)^2+(6)^2}$
Thus, we get $\ln \sqrt{49}=\ln 7$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 13 - Section 13.2 - Limits and Continuity in Higher Dimensions - Exercises - Page 691: 30
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