University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 13 - Section 13.2 - Limits and Continuity in Higher Dimensions - Exercises - Page 691: 27

Answer

$2$

Work Step by Step

Solve $\lim\limits_{(x,y,z) \to (3,3,0)}(1+\sec^2 z)$ Now, $\lim\limits_{(x,y,z) \to (3,3,0)}(1+\sec^2 z)=(1+\sec^2 (0))$ Thus, we get $(1+(1)^2)=2$
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