Answer
$-\dfrac{1}{2}$
Work Step by Step
Solve $\lim\limits_{(x,y,z) \to (1,-1,-1)}\dfrac{2xy+yz}{x^2+z^2}$
$\lim\limits_{(x,y,z) \to (1,-1,1)}\dfrac{2(1)(-1)+(-1)(-1)}{1^2+(-1)^2}=$
Thus, we get $\dfrac{-2+1}{1+1}=-\dfrac{1}{2}$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 13 - Section 13.2 - Limits and Continuity in Higher Dimensions - Exercises - Page 691: 26
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