## University Calculus: Early Transcendentals (3rd Edition)

$-1$
Solve the limit $\lim\limits_{(x,y) \to (1,1)} \dfrac{(x-1)(y-2)}{x-1}$ $\lim\limits_{(x,y) \to (1,1)} \dfrac{(x-1)(y-2)}{(x-1)}=\lim\limits_{(x,y) \to (1,1)}(y-2)$ Thus, $1-2=-1$