University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 13 - Section 13.2 - Limits and Continuity in Higher Dimensions - Exercises - Page 691: 15

Answer

$-1$

Work Step by Step

Solve the limit $\lim\limits_{(x,y) \to (1,1)} \dfrac{(x-1)(y-2)}{x-1}$ $\lim\limits_{(x,y) \to (1,1)} \dfrac{(x-1)(y-2)}{(x-1)}=\lim\limits_{(x,y) \to (1,1)}(y-2)$ Thus, $1-2=-1$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.