Answer
$\dfrac{1}{4}$
Work Step by Step
Here, we have $\dfrac{(1) \sin (\dfrac{\pi}{6})}{1^2+1}=\dfrac{1/2}{2}$
Thus, $(\dfrac{1/2}{2})=\dfrac{1}{4}$
University Calculus: Early Transcendentals (3rd Edition)
by Hass, Joel R.; Weir, Maurice D.; Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0321999584
ISBN 13:
978-0-32199-958-0
Chapter 13 - Section 13.2 - Limits and Continuity in Higher Dimensions - Exercises - Page 691: 11
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