Answer
$\dfrac{19}{12}$
Work Step by Step
Solve $\lim\limits_{(x,y,z) \to (1,3,4)}(\dfrac{1}{x}+\dfrac{1}{y}+\dfrac{1}{z})$
$\lim\limits_{(x,y,z) \to (1,3,4)}(\dfrac{1}{x}+\dfrac{1}{y}+\dfrac{1}{z})=(\dfrac{1}{1}+\dfrac{1}{3}+\dfrac{1}{4})$
Thus, we get $\dfrac{12+4+3}{12}=\dfrac{19}{12}$
