University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 13 - Section 13.2 - Limits and Continuity in Higher Dimensions - Exercises - Page 691: 25



Work Step by Step

Solve $\lim\limits_{(x,y,z) \to (1,3,4)}(\dfrac{1}{x}+\dfrac{1}{y}+\dfrac{1}{z})$ $\lim\limits_{(x,y,z) \to (1,3,4)}(\dfrac{1}{x}+\dfrac{1}{y}+\dfrac{1}{z})=(\dfrac{1}{1}+\dfrac{1}{3}+\dfrac{1}{4})$ Thus, we get $\dfrac{12+4+3}{12}=\dfrac{19}{12}$
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