University Calculus: Early Transcendentals (3rd Edition)

Published by Pearson
ISBN 10: 0321999584
ISBN 13: 978-0-32199-958-0

Chapter 13 - Section 13.2 - Limits and Continuity in Higher Dimensions - Exercises - Page 691: 12

Answer

$-2$

Work Step by Step

Here, we have $\dfrac{\cos (0)+1}{0-\dfrac{\pi}{2}}=\dfrac{1+1}{-1}$ Thus, $\dfrac{2}{-1}=-2$
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