Answer
$ x=1 $
Work Step by Step
Given $$ y =x^2+\frac{2}{x}$$
Then to find the critical points
\begin{align*}
y'&=0\\
2x-\frac{2}{x^2}&=0\\
\frac{2x^3-2}{x^2}&=0\\
2x^3-2&=0
\end{align*}
Hence the critical points is $ x=1 $
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 4: Applications of Derivatives - Section 4.1 - Extreme Values of Functions - Exercises 4.1 - Page 192: 45
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