Answer
$ x=1$ and $ x= 4$
Work Step by Step
Given $$ f(x) =x(4-x)^3$$
Then to find the critical points
\begin{align*}
f'(x)&=0\\
(4-x)^3-3x(4-x)^2&=0\\
[4-4x](4-x)^2&=0
\end{align*}
Hence the critical points are $ x=1$ and $ x= 4$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 4: Applications of Derivatives - Section 4.1 - Extreme Values of Functions - Exercises 4.1 - Page 192: 43
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
