Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 3: Derivatives - Section 3.6 - The Chain Rule - Exercises 3.6 - Page 148: 8


$y'=-sec(1/x+7x)tan(1/x+7x)\times (-1/x^2+7)$

Work Step by Step

First, find the derivative of y and u. Don't forget to apply chain rule for y': $y'=-secutanu\times u'$ $u'=-1/x^2+7$ Then plug in u and u' into y': $y'=-sec(1/x+7x)tan(1/x+7x)\times (-1/x^2+7)$
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