Answer
$s'=cos(\frac{3πt}{2})\times3π/2-sin(\frac{3πt}{2})\times3π/2$
Work Step by Step
Take the derivative and apply the chain rule:
$s'=cos(\frac{3πt}{2})\times3π/2-sin(\frac{3πt}{2})\times3π/2$
Thomas' Calculus 13th Edition
by Thomas Jr., George B.
Published by
Pearson
ISBN 10:
0-32187-896-5
ISBN 13:
978-0-32187-896-0
Chapter 3: Derivatives - Section 3.6 - The Chain Rule - Exercises 3.6 - Page 148: 22
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