Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 3: Derivatives - Section 3.6 - The Chain Rule - Exercises 3.6 - Page 148: 13



Work Step by Step

Find y and u: $y=u^4$ $u=x^2/8+x-1/x$ First, find the derivative of y and u. Don't forget to apply chain rule for y': $y'=4u^3\times u'$ $u'=x/4+1+1/x^2$ Then plug in u and u' into y': $y'=4(x^2/8+x-1/x)^3\times(x/4+1+1/x^2)$
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