Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 3: Derivatives - Section 3.6 - The Chain Rule - Exercises 3.6 - Page 148: 20


$q'=\frac{2-2r}{3\sqrt[3] (2r-r^2)^2}$

Work Step by Step

Take the derivative and apply the chain rule: $q'=1/3(2r-r^2)^{-2/3}\times(2-2r)=\frac{2-2r}{3\sqrt[3] (2r-r^2)^2}$
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