Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 3: Derivatives - Section 3.6 - The Chain Rule - Exercises 3.6 - Page 148: 1

Answer

$y'=12x^3$

Work Step by Step

First, find the derivative of y and u. Don't forget to apply chain rule for y': $y'=6u'$ $u'=2x^3$ Then plug u' into y'" $y'=6\times2x^3=12x^3$
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