Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 3: Derivatives - Section 3.6 - The Chain Rule - Exercises 3.6 - Page 148: 7



Work Step by Step

First, find the derivative of y and u. Don't forget to apply chain rule for y': $y'=sec^2u\times u'$ $u'=2πx$ Then plug in u and u' into y': $y'=2πxsec^2(πx^2)$
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