Answer
See below.
Work Step by Step
$f(x)$ is a polynomial, so it is continuous everywhere.
Note that
$f(-100)=-999,190$
$f(1000)=9,999,992$
Apply the Intermediate Value theorem.
If we take $[a,b]=[-100,1000]$ and select any $y_{0} \in(-999190, \ \ 9999992)$,
there must be a $c \in(-100,1000)$ such that $f(c)=y_{0}.$
$a.\quad y_{0}=\pi $ is such a number.
$b.\quad y_{0}=-\sqrt{3} $ is such a number.
$c.\quad y_{0}=5,000,000 $ is such a number.
(Other answers are possible.)
