Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 2: Limits and Continuity - Section 2.5 - Continuity - Exercises 2.5 - Page 85: 53

Answer

See the graph and explanation below.

Work Step by Step

Apply the Intermediate Value Theorem (IVT) for Continuous Functions: When $f(a)$ is negative, and $f(b)$ is positive, then $y_{0}=0$ is a value between $f(a)$ and $f(b).$ The IVT for continuous functions guarantees that that an $x=c\in(a,b)$ exists for which $f(c)=0$, that is, a solution of the equation $f(x)=0$ exists in $[a,b]$. What this means is that if the graph is below the x-axis at x=0, and above the x-axis at x=1, then at some point it has to cross the x-axis, because the function is continuous (no holes, no jumps, no infinite discontinuities).
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