Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 2: Limits and Continuity - Section 2.5 - Continuity - Exercises 2.5 - Page 85: 49

Answer

The function can be extended to a continuous function, A good candidate for $f(0)$:$\quad f(0)\approx 2.3026$

Work Step by Step

See the graph below. The function can be extended to a continuous function. Zooming, we define a good candidate for $f(0)$:$\quad f(0)\approx 2.3026$
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