Thomas' Calculus 13th Edition

Published by Pearson

Chapter 12: Vectors and the Geometry of Space - Section 12.5 - Lines and Planes in Space - Exercises 12.5 - Page 727: 33

Answer

$2 \sqrt {30}$

Work Step by Step

The distance formula for two vectors can be calculated as: $d=\dfrac{|p \times q|}{|q|}$ and $p \times q=\lt -24,-48,0 \gt$ and $|p \times q|=\sqrt{(-24)^2+(-48)^2+(0)^2}=24 \sqrt 5$ Thus, $d=\dfrac{24 \sqrt 5}{2 \sqrt 6}=2 \sqrt {30}$

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