## Thomas' Calculus 13th Edition

$(-4,-2,-5)$
Since, we are given that the parametric equations $x=-1+3t; y=-2; z=5t$ Equation of plane is: $2x-3z=7$ Plug all the parametric equations $x=-1+3t; y=-2; z=5t$ in the equation of plane, we get $t=-1$ Now, the parametric equations are $x=-1+3(-1)=-4; y=-2; z=5(-1)=-5$ Hence, the line will meet at the point: $(-4,-2,-5)$