Thomas' Calculus 13th Edition

Published by Pearson
ISBN 10: 0-32187-896-5
ISBN 13: 978-0-32187-896-0

Chapter 12: Vectors and the Geometry of Space - Section 12.5 - Lines and Planes in Space - Exercises 12.5 - Page 727: 56



Work Step by Step

Since, we are given that the parametric equations $x=-1+3t; y=-2; z=5t$ Equation of plane is: $2x-3z=7$ Plug all the parametric equations $x=-1+3t; y=-2; z=5t$ in the equation of plane, we get $t=-1$ Now, the parametric equations are $x=-1+3(-1)=-4; y=-2; z=5(-1)=-5$ Hence, the line will meet at the point: $(-4,-2,-5)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.